Llongyfarchiadau i:

Sian Hayward, Ysgol y Borth am gael yr ateb yn gywir y mis yma. Bydd gwerth £50 o feddalwedd ar ei ffordd i'r ysgol.

Noddir y
gystadleuaeth
gan gwmni
Gaia
Technologies,
Bangor

Dyma atebion Sian:
(9 + 2) + (4 x 5) + (6 x 8) + (3 x 7) x 1 = 100
(6 x 9) + (7 x 8) - 5 - 3 + 2 - 4 x 1 = 100
42 + 65 - 8 + [3 - (9 - 7) x 1] = 100
98 - 21 + (4 x 5) + [(7 - 6) x 3] = 100
92 - 35 + (6 x 7) + (8 ÷ 4) - 1 = 100
56 + 37 + (2 x 4) - 1 x (9 - 8) = 100
56 + 37 + [9 - (8 - 4) + 2] x 1 = 100
45 + (3 x 9) + (2 x 7) + 6 + 8 x 1 = 100
67 + (4 x 5) + 9 + 8 - 3 - 2 + 1 = 100
123 - (4 x 5) - (9 - 6) x (8 - 7) = 100
134 - (6 x 7) + (9 - 8) + 2 + 5 = 100
78 + (4 x 5) + (9 - 6) - 3 + (2 x 1) = 100
34 + (7 x 8) + (9 - 6) + 5 + (2 x 1) = 100
67 + (4 x 5) + (8 + 9) - 3 - 2 + 1 = 100
89 + 23 - [(4 + 6) + (7 - 5) x 1] = 100
46 + (5 x 9) + [(1 + 2) x 3] x (8 - 7) = 100
167 - (8 x 5) - (4 x 7) + (3 - 2) = 100